0.0045x^2-1.15x-10=0

Solution for 0.0045x^2-1.15x-10=0 equation:

0.0045x^2-1.15x-10=0

a = 0.0045; b = -1.15; c = -10;
Δ = b2-4ac
Δ = -1.152-4·0.0045·(-10)
Δ = 1.5025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.15)-\sqrt{1.5025}}{2*0.0045}=\frac{1.15-\sqrt{1.5025}}{0.009}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.15)+\sqrt{1.5025}}{2*0.0045}=\frac{1.15+\sqrt{1.5025}}{0.009}
$